(1.5t)-(5t^2)=X

Solution for (1.5t)-(5t^2)=X equation:

(1.5t)-(5t^2)=t

We move all terms to the left:

(1.5t)-(5t^2)-(t)=0

determiningTheFunctionDomain
-5t^2+(1.5t)-t=0

We add all the numbers together, and all the variables

-5t^2+(+1.5t)-t=0

We add all the numbers together, and all the variables

-5t^2-1t+(+1.5t)=0

We get rid of parentheses

-5t^2-1t+1.5t=0

We add all the numbers together, and all the variables

-5t^2+0.5t=0

a = -5; b = 0.5; c = 0;
Δ = b2-4ac
Δ = 0.52-4·(-5)·0
Δ = 0.25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.5)-\sqrt{0.25}}{2*-5}=\frac{-0.5-\sqrt{0.25}}{-10}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.5)+\sqrt{0.25}}{2*-5}=\frac{-0.5+\sqrt{0.25}}{-10}
$